Question

Find a counterexample to disprove the conjecture.

Answer 1

Answer:

D. mZCAB = 70° and mLDAB = 20°

Step-by-step explanation:

An angle bisector is a line that divides a given angle into two equal parts. From the given question:

if angle CAD is divided into two unequal angles by AB, then AB is not an angle bisector of ZCAD.

For example: let mCAD = $90^{o}$. Then if mCAB = mDAB = $45^{o}$, then AB is an angle bisector.

But if mCAB $\neq$ mDAB, then AB is not an angle bisector. Eg: mZCAB = 70° and mLDAB = 20°