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2 years ago

MZAOB = 6x- 12° mZBOC = 3x+ 30° Find mZAOB:

Mathematics

2 answers:

Debora [2.8K]2 years ago

7 0

Answer:

6x+3x×12-30

9x×do 30-12

then multiple it and there is the ans

Elanso [62]2 years ago

4 0

The answer is 14 hope is right

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Find the value(s) of n if n^4=625.

Grace [21]

The answer is 5 and -5, because squaring a positive or negative number give the same value, so square rooting that number should give back those positive and negative value. THIS ONLY WORKS FOR WHEN THE SQUARE ROOT OR THE SQUARING IS AN EVEN NUMBER.

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3 years ago

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What is the area of the circle with a D equals 10

Maslowich

Answer:

A =78.5

Step-by-step explanation:

We need the radius to find the area of a circle

r = d/2 = 10/2 =5

The area of a circle is given by

A = pi r^2

A = 3.14 (5)^2

A =3.14 (25)

A =78.5

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3 years ago

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2 years ago

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GalinKa [24]

Answer:

3(6) -1

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2(6)+1

Step-by-step explanation:

first find r(6)

r(6) =3(6) -1

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s(6) = 2(6)+1

Then divide

r(6)/s(6) = 3(6) -1

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2(6)+1

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3 years ago

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Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago