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Alona [7]
3 years ago
13

Maria invited 4 of her friends over for a water balloon fight in the back yard. At the start of the game Maria Gabe each of her

friends 2 water balloons. Shad one water balloon for her self . How many water balloons did they have altogether.
Mathematics
1 answer:
Liula [17]3 years ago
4 0
9 water balloons in total
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Answer:

The answer is #4

Step-by-step explanation:

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If your financial goal is to save at least $40,000 in 10 years, what would be the least
adoni [48]

<em><u>The least amount of money you would need to invest per month is; $335</u></em>

<em><u>The anticipated rate of return on your investments is; 7%</u></em>

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  • Amount to have been saved at the end of 10 years ≥ $40,000

Number of years of savings = 10 years.

  • We want to find out the least amount to be invested per month.

There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.

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  • Since the minimum amount he wants to save after 10 years is $40000, then we need to approximate the monthly savings in order.

Thus;

Monthly savings ≈ $335

  • Now, for the anticipated rate of return on the investment, we know from S & P's that the benchmark on good rate of return for investment is a minimum of 7%.

  • From online calculator, the worth of the investment after 10 years based on 7% rate of return yearly would be $57626.

Read more at; brainly.com/question/9187598

4 0
2 years ago
The radius of a circular puddle is growing at a rate of 25 cm/sec.
tatiyna

Answer:

Step-by-step explanation:

a)area A=pi r^2

rate of change of area =dA/dt =2 pi r dr/dt

given dr/dt =25 ,r =50

rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854

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b)area A=pi r^2

rate of change of area =dA/dt =2 pi r dr/dt

given dr/dt =25 ,A =64

pi r^2 =64

=>r =8/√pi

rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98

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Answer:

A, D

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This is also equivalent to:

5^{-4}

When looking at the answer choices, the only ones that equal 5^{-4} are A and D because:

(5^{-2})^{2}  =5^{-4}

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Answer:

Segment EF is twice as long as segment AB.

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