Multiplied by the cross
4/15 = x /75
15•x=4•75
15x=300
x= 300 : 15
x=20
t/9 = 35/6
9•35 = t•6
315 =6t
315 : 6 = t
52,5 = t
Answer:

Step-by-step explanation:
Given
Shape: Cube
Dimension: (x+7y), (7x-y) and (xy-5).
Required
Determine the volume
The volume is calculated by multiplying the dimensions:

Evaluate the first 2 brackets
![Volume = [x(7x-y)+7y(7x-y)] * (xy-5)](https://tex.z-dn.net/?f=Volume%20%3D%20%5Bx%287x-y%29%2B7y%287x-y%29%5D%20%2A%20%28xy-5%29)
![Volume = [(7x^2-xy)+(49xy-7y^2)] * (xy-5)](https://tex.z-dn.net/?f=Volume%20%3D%20%5B%287x%5E2-xy%29%2B%2849xy-7y%5E2%29%5D%20%2A%20%28xy-5%29)
![Volume = [7x^2-xy+49xy-7y^2] * (xy-5)](https://tex.z-dn.net/?f=Volume%20%3D%20%5B7x%5E2-xy%2B49xy-7y%5E2%5D%20%2A%20%28xy-5%29)
![Volume = [7x^2+48xy-7y^2] * (xy-5)](https://tex.z-dn.net/?f=Volume%20%3D%20%5B7x%5E2%2B48xy-7y%5E2%5D%20%2A%20%28xy-5%29)
Open brackets
![Volume = xy[7x^2+48xy-7y^2] -5[7x^2+48xy-7y^2]](https://tex.z-dn.net/?f=Volume%20%3D%20xy%5B7x%5E2%2B48xy-7y%5E2%5D%20-5%5B7x%5E2%2B48xy-7y%5E2%5D)

Answer:
It would take 12.1 years.
Step-by-step explanation:
We are given with $3000 invested in bank pays 6.75% interest compounded semi annually to the nearest 10th. We are asked to find the number of years the bank reaches $6700.
Let's use the compound interest formula.

We know A=6700
P=3000
r =0.0675
n=2(because compounded semiannually)
t =?( we need to find it)
Plug in the known values into the formula.

Simplify and solve for 't'
Divide both sides by 3000

Take log on both sides

Divide both sides by log(1.03375)
24.2067=2t
Divide both sides by 2.
t=12.10...
To round to nearest 10th, we get t=12.1 years.
22.4 × 10.2 ÷2 = 220.8÷2=110.4
Division of a fraction is the equivalent of multiplying by its reciprocal
ex.

i suggest you try to remember this concept
in terms of your question
from this point, just multiple the numerators together and denominators together, then simplify if necessary
fyi- difference of squares

relating that to

also a side note, you might want to factor out the 4 first in the top fraction