All categories

3 years ago

Goal is to make $100. What % of the goal was met if raised $350?

Mathematics

1 answer:

slega [8]3 years ago

7 0

______________________________

<h3>A = m ÷ t × 100</h3><h3>= $100 ÷ $350 × 100</h3><h3>= <u>28.6%</u></h3><h3>THE GOAL WAS SURPASSED BY 28.6%</h3>

______________________________

You might be interested in

What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis

Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

Step-by-step explanation:

$\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}$

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0

3 years ago

Read 2 more answers

Each unit cube measured 1 inch3. what is the maximum volume of the prims

Vesnalui [34]

Answer:

1 x 3 x 1 = 3

Step-by-step explanation:

4 0

3 years ago

Two angles are supplementary the first angle measures 40 degrees what is the second angle

nydimaria [60]

The second angle would be 140⁰. When two angles are supplementary, they add up to 180⁰.
180⁰-40⁰=140⁰

4 0

3 years ago

For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth

murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.

You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.

-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)

Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.

-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)

Now we can use the factors of two perfect squares rule to factor the middle parenthesis.

-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)

We would also want to split the term in the front.

-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)

Now we would set each portion equal to 0 and solve.

First root

x = 0 ---> no work needed

Second root

-x = 0 ---> divide by -1

x = 0

Third root

x - 2 = 0

x = 2

Forth root

x + 2 = 0

x = -2

Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- $\sqrt{-1}$

x = +/- i

7 0

3 years ago

Which system of linear inequalities is graphed? {y>3x−2x+2y<4 {y≥3x−2x+2y≤4 {y≤3x−2x+2y≥4 {y<3x−2x+2y>4 A graph of a

guajiro [1.7K]

Answer:

{y≥3x−2

{x+2y≤4

3 0

3 years ago