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wolverine [178]
4 years ago
10

Which statement is true about Angle B P D? Line A B intersect line C D at point P. It is adjacent to Angle A P C. It is compleme

ntary to Angle B P C. It is congruent to Angle A P C. It is linear to Angle A P C.

Mathematics
2 answers:
mel-nik [20]4 years ago
7 0

Answer:

It is congruent to Angle A P C

Step-by-step explanation:

we know that

<u><em>Vertical angles</em></u> are the angles opposite each other when two lines cross. They are always congruent.

In this problem we have that

m\angle APC=m\angle BPC -----> by vertical angles

see the attached figure to better understand the problem

therefore

It is congruent to Angle A P C

mart [117]4 years ago
6 0

Answer:

ints congeuent

Step-by-step explanation:

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Artist 52 [7]

Answer:

b) f(x) = x + 6

Step-by-step explanation:

The coordinate (0, 6) makes the y-intercept = 6. Only one of these functions has that intercept: f(x) = x + 6. If you plug in each coordinate the outputted y-value matches up, making this the right answer.

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3 years ago
Help<br><br> (5a-3a^3)*(4a-1)
ivann1987 [24]

Answer:

-12a^{4}  + 3a^{3} + 20a^{2} -5a

Step-by-step explanation:

(5a-3a^{3} ) • (4a-1)

Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.

20a^{2} - 5a - 12a^{4} + 3a^{3}

Rearrange in decreasing exponents.

-12a^{4}  + 3a^{3} + 20a^{2} -5a

3 0
3 years ago
ILL GIVE YOU BRAINLIEST!! Which number is rational?
Dmitry [639]

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Write the equation of the line described in point-slope form. Then, change to Standard Form. Contains points (3/2,-1/2) and (-1/
larisa [96]
Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)

But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2

Now we can place it in slope point and also in standard form of a line.

Y-y1 = m(X -X1)

Y - -1/2 = -3/2(X - 3/2)

Y + 1/2 = -3/2(X - 3/2)

This is in slope point form.

Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
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This is in standard form. If you have any questions of the steps just ask.
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3 years ago
Evaluate the expression
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