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3 years ago

1. Solve the system using substitution. (1 point)

Mathematics

1 answer:

LenKa [72]3 years ago

8 0

Step-by-step explanation:

Just plug in y

New equation is:

x + 3r = 8

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Sumara Kato's savings account has a balance of $1663. After 19 years, how much interest

lesantik [10]

Answer: $2936.27

Step-by-step explanation:

Present value = $1663

Rate = 5.5%

Time(n) = 19years

Future value= PV(1+r)^n

= 1663(1+5.5%)^19

= 1663(1.055)^19

=1663 × 2.766

=4599.86

Interest = Future value - Present value

= $4599 - $1663

= 2936

4 0

4 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

4 years ago

Find the product and write ot in the lowest terms. 6 over 7 × 9 over 4

Nikitich [7]

Answer:

27/14

Step-by-step explanation:

you can cross multiply and simplify before you start. that way it makes it a lot easier

7 0

4 years ago

Niu earned $312 on an investment of $800. How much would $1100 have earned in the same

steposvetlana [31]

Answer:

429

Step-by-step explanation:

312/800 = .39

1100 x .39 = 429

5 0

4 years ago

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Please help ASAP if you know how. Thanks so much

zlopas [31]

I’m not so sure i’m sorry

6 0

3 years ago

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