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vekshin1
3 years ago
6

Why do surfers put wax on their boards​

Chemistry
2 answers:
poizon [28]3 years ago
5 0

Answer:

to keep the surfer from slipping off the board

Explanation:

Surfboard wax (also known as surfwax) is a formulation of natural and/or synthetic wax for application to the deck of a surfboard, bodyboard, or skimboard, to keep the surfer from slipping off the board when paddling out or riding a wave. It is also used to increase grip on the paddle of a surf kayak or dragon boat.

VikaD [51]3 years ago
4 0

Answer:

Surfboard wax (also known as surfwax) is a bodyboard, or skimboard, to keep the surfer from slipping off the board when paddling out or riding a wave. It is also used to increase grip on the paddle of a dragon boat or surf board.

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When 2 grams of Hydrogen (H2) react with 32 grams of Oxygen (O2) the reaction yields hydrogen peroxide (H2O2). How many grams of
Alisiya [41]

<u>Given information:</u>

Mass of H2 = 2 g

Mass of O2 = 32 g

<u>To determine:</u>

Mass of H2O2 produced

<u>Explanation:</u>

The reaction between H2 and O2 can be given as:

H2 + O2 → H2O2

Based on the reaction stoichiometry:

1 mole of H2 reacts with 1 mole of O2 to form 1 mole of H2O2

# moles of H2  = mass of H2 / molar mass of H2 = 2 g/ 2 g.mol-1 = 1 mole

# moles of O2 = mass of O2/ molar mass of O2 = 32 g/ 32 g.mol-1 = 1 mole

Hence for the given reactant conditions, moles of H2O2 produced = 1

Mass of H2O2 = moles of H2O2 * molar mass H2O2 = 1 mole * 34 g.mole-1 = 34 g

<u>Ans</u>: 34 g of H2O2 is produced in this reaction

8 0
3 years ago
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What was the main use of constellations in ancient times?
Whitepunk [10]

Answer:

the ans is option b(help navigate at night)

3 0
3 years ago
Convert 10kg⋅cm/s^2 to newtons
Solnce55 [7]

Answer:

one newton

Explanation:

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3 0
3 years ago
How many moles of atoms are there in 27g of aluminium
Marrrta [24]
We know that the molar mass of Al is 27 g/mol.

27 g Al* (1 mol Al/ 27 g Al)= 1 mol Al.

The final answer is 1 mol Al~
4 0
4 years ago
The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 via a combust
bearhunter [10]

<u>The answer is </u><u>9.94 ml.</u>

<h3>What is density?</h3>
  • Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
  • Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.

Given,

        The density of ethanol, C2H5OH = 0.789 g/mL

n (CO_{2} ) = \frac{m}{M}  = \frac{15G}{44 g/mol} } = 0.341 mol;

n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2}  = \frac{0.341}{2}  = 0.1705  mol;

m (C_{2} H_{2} OH) = 0.1705 mol * 46  g/ mol = 7.843 g

V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.

Therefore, the answer is 9.94 ml

Learn more about density of ethanol,

brainly.com/question/18597444

#SPJ4

<u>The complete question is -</u>

If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

5 0
2 years ago
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