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Nady [450]
3 years ago
7

In the equation c2h4 + 3o2 = ? co2 + 2h2o, how many co2 molecules are needed to balance the equation?

Chemistry
1 answer:
AVprozaik [17]3 years ago
8 0
C2H4 +3O2 =?CO2 +2H2O
The number  of CO2  molecule s that are needed to balance the  equation are

two (2)

that is  C2H4 +3O2 = 2CO2+ 2H2O

1 molecule of   ethane (C2H4)  is burned in presence of oxygen to form 2 molecules of carbon(iv) oxide (CO20 and 2 molecules of water(H2O)
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How many grams of NaCl (molecular weight = 58.4 g mole-1) would you dissolve in water to make a total volume of 500 mL of soluti
kolezko [41]

Given :

Volume , V = 500 mL .

Molarity , M = 0.5 M .

Molecular mass of NaCl is 58.4\ g/mole .

To Find :

How many grams of NaCl is required .

Solution :

Let , NaCl required is x gram .

Molarity is given by :

M=\dfrac{\text{Number of moles}}{\text{Volume (in liters) }}\\\\M=\dfrac{m}{M\times V}\\\\0.5=\dfrac{x}{58.4\times 0.5}\\\\x=0.5^2\times 58.4\ g\\\\x=14.6\ g

Hence , this is the required solution.

6 0
2 years ago
Pls help me on this it’s past due ty
mihalych1998 [28]

Answer:

sorry

Explanation:

6 0
2 years ago
Ammonia reacts with sulfuric acid to produce the important fertilizer, ammonium hydrogen sulfate.
Liula [17]

Answer:

404.8g of (NH4)HSO4 is produced.

Explanation:

Step 1:

Data obtained from the question. This include the following:

Temperature (T) = 10°C = 10°C + 273 = 283K

Pressure (P) = 110KPa = 110/101.325 = 1.09atm

Volume (V) = 75L

Step 2:

Determination of the number of mole of ammonia, NH3.

The number of mole (n) of ammonia, NH3 can be obtained by using the ideal gas equation. This is illustrated below:

Note:

Gas constant (R) = 0.0821atm.L/Kmol

Number of mole (n) =?

PV = nRT

1.09 x 75 = n x 0.0821 x 283

Divide both side by 0.0821 x 283

n = (1.09 x 75) /(0.0821 x 283)

n = 3.52 moles

Step 3:

Determination of the number of mole ammonium hydrogen sulfate produced from the reaction.

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH3 + H2SO4 —> (NH4)HSO4

From the balanced equation above,

1 mole of NH3 produced 1 mole of (NH4)HSO4

Therefore, 3.52 moles of NH3 will also produce 3.52 moles of (NH4)HSO4.

Therefore, 3.52 moles of ammonium hydrogen sulfate, (NH4)HSO4 is produced.

Step 4:

Conversion of 3.52 moles of ammonium hydrogen sulfate, (NH4)HSO4 to grams. This is illustrated below:

Molar Mass of (NH4)HSO4 = 14 + (4x1) + 1 + 32 + (16x4) = 115g/mol

Number of mole of (NH4)HSO4 = 3.52 moles

Mass of (NH4)HSO4 =..?

Mass = mole x molar Mass

Mass of (NH4)HSO4 = 3.52 x 115 = 404.8g

Therefore, 404.8g of (NH4)HSO4 is produced.

5 0
2 years ago
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4
forsale [732]
The molarity of H2SO4 is the number of moles in 1 L of solution.
The molarity is 2.0 mol/L
This means that there should be 2 moles in a 1 L solution to make up this molarity.
In this case we need to make up a 5 L solutions with that molarity. Then the amount of moles required are - 2 mol/L x 5 L = 10 mol
3 0
2 years ago
Read 2 more answers
What is the chemical name for a compound with the formula ba3n2?
LekaFEV [45]
Barium nitride 

copy the name of the metal as it is written in the periodic table and the first part of the name of the nonmetal (nitrogen)  and replace the end by "ide"
3 0
3 years ago
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