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4 years ago

In the equation c2h4 + 3o2 = ? co2 + 2h2o, how many co2 molecules are needed to balance the equation?

1 answer:

8 0

C2H4 +3O2 =?CO2 +2H2O
The number of CO2 molecule s that are needed to balance the equation are

two (2)

that is C2H4 +3O2 = 2CO2+ 2H2O

1 molecule of ethane (C2H4) is burned in presence of oxygen to form 2 molecules of carbon(iv) oxide (CO20 and 2 molecules of water(H2O)

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How many moles are in 10 mg of NO2

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mole=10 x 10⁻³ : 46 g/mol = 2.17 x 10⁻⁴

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Which condition must be met in order for an equation to be balanced?

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Answer:

The elements in the reactants are the same as the elements in the products.

Explanation:

You can't have more or less elements or atoms, but you also can't just have the same number of atoms because then it could be different elements, which can't happen.

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5. Which of the following has variable composition<br>A. Water<br>B. sugar<br>C, soil<br>D. Salt

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Answer:

C. Soil

Explanation:

The choice with variable composition is the soil. Soil have many different composition.

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3 years ago

Question 2 of 50

wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

Write the balanced chemical equation for the given reaction.
Convert the mass of calcium carbonate into moles.
Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

$CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}$

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

$mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}$

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

$mol \ CaO \ = 0.2498 \ mol$

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

$mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g$

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

$\boxed {mass \ CaO \ = 14 \ g}$

Learn More

Learn more about stoichiometry brainly.com/question/12979299
Learn more about mole conversion brainly.com/question/12972204
Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

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3 years ago

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