In this kind of exercises, you should use the "ideal gas" rules: PV = nRT
P should be in Pascal:
445mmHg = 59328Pa
1225mmHg = 163319Pa
V should be in cubic meter:
16L = 0.016 m3
R =
= constant
=
==> P1 * V1 = P2 * V2
V2 =
=
V2 = 0.00581 m3 = 5.81 L
Qualitative (physical e. g. colour) and quantitative (numerical e. g. 3 grams) data
Answer:
0.31 mole
Explanation:
The following data were obtained from the question:
Mass of SF6 = 45.0 g
Number of mole of SF6 =..?
Next, we shall determine the molar mass of SF6.
This can be obtained as follow:
Molar mass of SF6 = 32 + (19×6)
Molar mass of SF6 = 32 + 114
Molar mass of SF6 = 146 g/mol
Finally, we shall determine the number of mole in 45 g of SF6 as follow:
Molar mass of SF6 = 146 g/mol
Mass of SF6 = 45.0 g
Number of mole of SF6 =..?
Number of mole = mass /Molar mass
Number of mole of SF6 = 45 /146
Number of mole of SF6 = 0.31 mol
Therefore, 0.31 mol is present in 45 g of SF6.
The Sun
Explanation:
Because it's to hot to live on
Answer:
I think A is the correct answer