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erma4kov [3.2K]
3 years ago
7

PLSSSSS HELP!!

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0

Answer:

p = 10.5b

Step-by-step explanation:

The equation has this form:

y = ax+c

  • a = \frac{21-0}{2-0}
  • a = 21/2
  • a= 10.5

so the slope is 10.5

c is the y-intercept wich is given by the output of 0

here it's 0

  • 0⇒0

so the equation is y = 10.5x ⇒ p=10.5b

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What is the volume of the composite figure?
Tom [10]

Answer:

The volume of the composite figure is 140 in³

8 0
3 years ago
Is 15 a repeating decimal
Paul [167]

Answer: YES!

Step-by-step explanation:

The greatest common factor (GCF) of 1 and 15 is 1. Convert 1/15 to its simplest form by dividing the numerator and denominator by its GCF

The prime factors of 15 are all the prime numbers that you multiply together to get 15. The prime factors of 15 are:

3 x 5

A fraction is a repeating decimal if the prime factors of the denominator of the fraction in its lowest form do not only contain 2s and/or 5s or do not have any prime factors at all. This is the case here, which means that our answer is as follows:

1/15

= repeating

8 0
2 years ago
22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p
Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

S_{n+1}=1.05*S_n+1000\\\\S_0=50000

(b) The salary 25 years after 2017 will be $217044.85.

(c) S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

Step-by-step explanation:

We can define the next year salary S_{n+1} as

S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)

Extending to 3 years (n+3)

S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)

Extending to 4 years (n+4)

S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)

We can now express a general equation for S_n (salary at n years from 2017)

S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

The salary at 25 years from 2017 (n=25) will be

S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85

8 0
4 years ago
Hello! :)
Bumek [7]
The answer B makes the most sense out of all because s and b are congruent and that’s the only two there
5 0
3 years ago
Read 2 more answers
How can I do this dudhhehrhr
Ludmilka [50]

Answer:

the answer is 30

Step-by-step explanation:

(6+4) * 3

Do what is in the parenthesis!

(6+4) = 10

Then do the *3

10*3 = 30!

Hope this help! Goodluck!

6 0
3 years ago
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