The probability that you randomly draw a short straw from a group of 80 straws is 3/20. How many are short straws?

Z-2w=2 please help me solve , studying for praxis

RUDIKE [14]

Answer:

Z(2w-2)=24

Simple and best practice solution for Z(2w-2)=24 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

5 0

2 years ago

Using the diagram on the right, find the length of GT and TA.

Art [367]

Answer:

$GT=10\ units$ and $TA=6\ units$

Step-by-step explanation:

we know that

In the diagram

Triangles GRT and GEA are similar by AA Similarity Postulate

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

$\frac{GR}{GE}=\frac{GT}{GA}$

we have

$GR=5\ units$

$GE=5+3=8\ units$

$GT=16-x\ units$

$GA=16\ units$

substitute

$\frac{5}{8}=\frac{16-x}{16}\\ \\5*16=8*(16-x)\\ \\80=128-8x\\ \\8x=128-80\\ \\x=48/8\\ \\x=6\ units$

therefore

$GT=16-x=16-6=10\ units$

$TA=x=6\ units$

5 0

3 years ago

Jessica's heart beats 12 times in 1/6 minute how many times does her heart beat each minute

Charra [1.4K]

Answer:

72

Step-by-step explanation:

12 6 times equals 72.

12x6=72

4 0

3 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago

14 through 19 whole problem solving and answers

Sergio039 [100]

SEE THE PICTURE!~,BELOW~

4 0

3 years ago

Read 2 more answers