Answer:
The answer is "Market" economy
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<span>P(t) = Po(1 - r)^t
P(t) = price after t months --> S
Po = initial price -- P
r = rate as a decimal
S = P(.9)^4
-> = 100(.9)^4
-> = 65.61
(100 - 65.61)/100
34.39/100
34%</span>
Answer:

Step-by-step explanation:
Hello!
To find the slope of a line we divide how many times it goes over by the number of times it goes up
The line goes over 4 and up 2 which is shown like

We can simplify this

The answer is 
Hope this helps!
Answer:
(3 V/ 4 pi) ^(1/3) = r
Step-by-step explanation:
The volume of a sphere is given by
V = 4/3 pi r^3
We want to solve for r
Multiply each side by 3/4
3/4 V = 4/3*3/4 pi r^3
3/4 V = pi r^3
Divide each side by pi
3/4 V/ pi = pi/pi r^3
3 V/ 4 pi = r^3
Take the cube root of each side
(3 V/ 4 pi) ^(1/3) = ( r^3) ^1/3
(3 V/ 4 pi) ^(1/3) = r
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5