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3 years ago

How does the graph look for this?

Mathematics

1 answer:

Alenkinab [10]3 years ago

8 0

Answer:

The lines are right on top of each other.

Step-by-step explanation:

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Points gyfridjwnxsbhjkjh

Art [367]

Answer:hey

Step-by-step explanation:ur cool

7 0

2 years ago

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If b = 10 then a = 5<br><br> what id 2b+5a

MrRa [10]

2(10) +5(5)= 45

b=10 a=5

Plug in the values b and a.

7 0

2 years ago

Select all of the words that represent the answer to a quadratic equation (there are 4 answers).

Inessa [10]

Answer:

see explanation

Step-by-step explanation:

The words used to represent answers to a quadratic equation are

• x- intercepts

• solutions

• roots

• zeros

5 0

3 years ago

Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu

Murljashka [212]

Answer:

The value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=30t-\frac{g_s}{2} t^2$

Velocity is defined as the rate of change of position. Therefore,

$v(t)=\frac{d}{dt}(s(t))$

So, the velocity function is

$v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st$

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

$v(t)=30-g_st=0\\\\g_s=\frac{30}{t}$

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).

So, the value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

5 0

3 years ago

Is 8/9 greater than 5/10

Agata [3.3K]

Yes 8/9 is greater than 5/10

5 0

3 years ago

Read 2 more answers