Coordinate and it's reflection over the x- axis be an even number

Solve -52 = 4m for m

ZanzabumX [31]

Note the equal sign. What you do to one side, you do to the other.

Isolate the variable. Divide 4 from both sides

(-52)/4 = (4m)/4

m = -52/4

m = -13

-13 is your answer for m

hope this helps

8 0

3 years ago

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Please help 20 points

12345 [234]

Answer:

x =± (√ 317/ 2 )+( 15 /2)

6 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

Each bucket holds 325 gallons of water. If it takes 6 buckets to fill a tank, how much water does the tank hold?

Gemiola [76]

Answer:

1950

Step-by-step explanation:

if we do 325 gallons of water times 6 buckets of water we get 1,950 gallons of water in a fraction 325/1950

hope this helps

8 0

2 years ago

a fisherman weighs an ahi tuna (a very large fish) on a scale and gets a reading of 135 pounds. the reading on the scale may hav

mamaluj [8]

Answer:

Coin 1 = quarter

Coin 2 = dine

Coin 3 = penny

Step-by-step explanation:

8 0

3 years ago

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