Coordinate and it's reflection over the x- axis be an even number
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
let side of cube=x cm
volume=x³ cm³
again side=(x-3) cm
volume=(x-3)³ cm³
x³-(x-3)³=1385
(a³-b³)=(a-b)(a²+ab+b²)
(x-x+3){x²+x(x-3)+(x-3)²}=1385
3(x^2+x²-3x+x²-6x+9)=1385
3(3x²-9x+9)=1385
9x²-27x+27=1385
9x²-27x+27-1385=0
9x²-27x-1358=0
your question is incomplete, here you can find the complete question below:
An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.
a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?
b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?
c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?
Answer:
a. 1.45
b. 2.56
c. 3.59
Step-by-step explanation:
As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.
It is given that initial point is (x1,y1)=(0,0)
Part(a)
initial point is (x1,y1)=(0,0)
terminal point is (x2,y2)=(3.38,2.32)
so the slope of the terminal ray is
Part(b)
initial point is (x1,y1)=(0,0)
terminal point is (x2,y2)=(1.49,3.82)
so the slope of the terminal ray is
Part(c)
initial point is (x1,y1)=(0,0)
terminal point is (x2,y2)=(1.1,3.95)
so the slope of the terminal ray is