Answer:
D. Vertex: (3, -1); zeros: (2,0), (4,0), y-intercept: (0,8)
Step-by-step explanation:
I used the desmos graphing calculator. Just plug in your equation and it should be pretty easy to find these points
Answer:
15x+30
Step-by-step explanation:
multiply 15 and x + multiply 15 and 2
15x+30
Total number of numerals = 10
Total number of numerals to be used = 6
We are to find the number of different codes that can be formed and those can be found by permutations.
We have to find the permutations of 10 numerals taken 6 at a time. So we are to find 10P6.
10P6 = 151200
So, 151200 different codes can be formed.
So the answer to this question is option A