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3 years ago

14

Hello can you please help me posted picture of question

1 answer:

cestrela7 [59]3 years ago

6 0

Total number of numerals = 10
Total number of numerals to be used = 6
We are to find the number of different codes that can be formed and those can be found by permutations.

We have to find the permutations of 10 numerals taken 6 at a time. So we are to find 10P6.

10P6 = 151200

So, 151200 different codes can be formed.

So the answer to this question is option A

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Step-by-step explanation:

The parent should know how to figure ...

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3 years ago

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podryga [215]

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Step-by-step explanation:

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2 years ago

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saveliy_v [14]

Answer:

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y = 2(13) + 3

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2 years ago

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choli [55]

Answer:

Step-by-step explanation:

From the given information:

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$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

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here;

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$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

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Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

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Answer:

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