All categories

3 years ago

Helpp me plzz i will mark the branliest

Mathematics

1 answer:

lilavasa [31]3 years ago

3 0

Answer:

ok I'll help you

that's because

I'm a helpful guy

I'm grateful

I never ask people to thank me back

I'm smart and cunning enough to answer anything

So, bless my soul

AND THANK YOU

You might be interested in

Brandon mows his lawn once every 4 days. Thomas mows his lawn once every 3 days. Celena mows her lawn once every 6 days. If they

lakkis [162]

Answer: The Answer is 12

Step-by-step explanation: This is because each number's LCM (Least Common Multiple) is 12. Ex. 4,8,12 3,6,9,12 6,12

7 0

3 years ago

Read 2 more answers

Find the area of the regular pentagon. 4.1 cm 6 cm Area = [?] cm? Enter your answer to the nearest tenth.

Assoli18 [71]

Answer:

Area of the given regular pentagon is 61.5 cm².

Step-by-step explanation:

Area of a regular polygon is given by,

Area = $\frac{1}{2}aP$

Here, a = Apothem of the polygon

P = Perimeter of the polygon

Apothem of the regular pentagon given as 4.1 cm.

Side of the pentagon = 6 cm

Perimeter of the pentagon = 5(6)

= 30 cm

Substituting these values in the formula,

Area = $\frac{1}{2}(4.1)(30)$

= 61.5 cm²

Therefore, area of the given regular pentagon is 61.5 cm².

8 0

3 years ago

Angle K measures 67º and angle L measures 119°.

DaniilM [7]

Answer:

C. m Angle M = 113o and m Angle N = 61o

Step-by-step explanation:

It's the only answer that makes all the angles added together equal 360 degrees.

67 + 119 + 113 + 61 = 360

5 0

3 years ago

Read 2 more answers

Write an R-program to sample n = 1000 values from the BlackwellMacQueen Pólya urn for µ = αH where H is a non-atomic bivariate d

earnstyle [38]

poyo and churizzo uiouigyuftydfyitfogpghlhbl

8 0

3 years ago

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

3 years ago