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motikmotik
3 years ago
13

PLZ HELP QUICK............

Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

4^m

Step-by-step explanation:

When you exponent an exponent, you multiply the powers together.

When you divide exponents, you subtract the powers.

Step 1: Convert to same base

log₄64 = 3

Step 2: Rewrite equation

\frac{(4^3)^{0.5m}}{4^{0.5m}}

Step 3: Simplify

\frac{4^{1.5m}}{4^{0.5m}}

Step 4: Simplify

4^m

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The ratio of people who wanted hot dogs to hamburgers was 5:8. If 52 meals were served how many of those were hot dogs and hambu
nata0808 [166]

Answer:

32 hamburgers, 20 hot dogs

Step-by-step explanation: 5+8=13. then you divide 52 by 13 that equals 4 and then multiply the hot dog 5 times 4 = 20 and 8 times 4= 32

5 0
2 years ago
(24 + 4) ÷ 2 = (24 ÷ 2) + ( __ ÷ 2)<br><br> i dont know this
tensa zangetsu [6.8K]

Answer:

4

Step-by-step explanation:

(24+4) ÷ 2 = (24 ÷ 2) + (4 ÷ 2)

28÷2 = 14

Check:

24÷2 = 12

4÷2 = 2

12+2=14

3 0
3 years ago
Read 2 more answers
What does -3+7y=5x+2y Equal<br> (I’m bad at math)
bogdanovich [222]

Answer: 22 /5

-3+7y=5x+2y

Step-by-step explanation:

Subtract 2y from each side

-3+7y-2y=5x+2y-2y

-3 +5y = 5x

Add 5 to each side

5y = 5x+3

Divide each side by 5

y = 5x/5 +3/5

y = x +3/5

Let x = -5

y = -5 + 3/5

y = -25/5 +3/5

y = -22/5

Step-by-step explanation:

5 0
3 years ago
The square of a number is 12 more than four times the number?
Bas_tet [7]
X^2 = 4x + 12
x^2 - 4x - 12 = 0, use the quadratic equation
Solve for x over the real numbers:
(x - 6) (x + 2) = 0
Split into two equations:
x - 6 = 0 or x + 2 = 0
Add 6 to both sides:
x = 6 or x + 2 = 0
Subtract 2 from both sides:
Answer:  x = 6 (or x = -2 only positive solution)
4 0
3 years ago
The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find
9966 [12]

Answer:

<em>The particular integral of given differential equation</em>

<em>                  </em>y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))<em></em>

<em> General solution of given differential equation</em>

<em>      </em>y = y_{c} + y_{p}<em></em>

<em>  </em>Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))<em></em>

<em></em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given Differential equation  y'' − 5 y' + 4 y = x

Given equation in operator form

        D²y - 5 Dy +  4 y = x

⇒     ( D² - 5 D +  4 ) y =x

⇒    f(D) y = Q

where  f(D) = D² - 5 D +  4 and Q(x) = x

<em>The auxiliary equation  f(m) =0</em>

<em>           m²-5 m + 4 =0</em>

         m² - 4 m - m + 4 =0

        m ( m -4 ) -1 ( m-4) =0

         (m - 1) =0   and ( m-4) =0

        <em> m = 1 and m =4</em>

<em>The complementary function </em>

<em></em>Y_{c} = C_{1} e^{x} + C_{2} e^{4x}<em></em>

<u><em>Step(ii)</em></u>:-

<u><em>particular integral</em></u>

<em>Particular integral</em>

<em>     </em>y_{p} = \frac{1}{f(D)} Q(x) = \frac{1}{D^{2}  - 5 D +  4} X<em></em>

<em>taking common '4' </em>

<em>                          </em>= \frac{1}{4(1 +  (\frac{D^{2}  - 5 D}{4} ))} X<em></em>

<em>                         </em>

<em>                           </em>=\frac{1}{4}  (1 + (\frac{D^{2} -5D}{4})^{-1} )} X<em></em>

<em>applying binomial expression</em>

<em>      ( 1 + x )⁻¹    = 1 - x + x² - x³ +.....       </em>

<em>                          </em>=\frac{1}{4}  (1 - (\frac{D^{2} -5D}{4}) +((\frac{D^{2} -5D}{4})^{2} -...} )X<em></em>

<em>Now simplifying and we will use notation D = </em>\frac{dy}{dx}<em></em>

<em>                        </em>=\frac{1}{4}  (x - (\frac{D^{2} -5D}{4})x +((\frac{D^{2} -5D}{4})^{2}(x) -...}<em></em>

<em>Higher degree terms are neglected</em>

<em>                     </em>=\frac{1}{4}  (x - (\frac{ -5 D}{4}) x)<em></em>

<em>The particular integral of given differential equation</em>

<em>                  </em>y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))<em></em>

<u><em>Final answer</em></u><em>:-</em>

<em>          General solution of given differential equation</em>

<em>      </em>y = y_{c} + y_{p}<em></em>

<em>  </em>Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))<em></em>

<em></em>

<em></em>

<em>         </em>

<em> </em>

     

4 0
3 years ago
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