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2 years ago

I need to know I'm not sure if it is but I think it's not a function

Mathematics

1 answer:

notka56 [123]2 years ago

5 0

Answer:

This is a function.

Step-by-step explanation:

To be a function every x must have only one y as its partner. In this format (two ovals with numbers in them and arrows showing the pairs) If EVERY x has only ONE arrow pointing away from it, then it is a function. If any x has MORE THAN ONE arrow pointing away from it, at two different y-numbers, then it is NOT a function.

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Last one yall pls help me!

Xelga [282]

Answer:

8. 5/6

9. 6.25 or 6 1/4

10. 14.4 Fish

Step-by-step explanation:

8. Reduce the fraction. (20/24) You can divide both the numerator and denominator by 4.

9. Divide 75 by 12

10. Divide 72 by 5

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3 years ago

PLEASE PLEASE HELP ME ASAPPP

Ivenika [448]

Answer:

a. 14:45pm (It's really easy to convert to a 24-hour clock time, all you need to do is add 12 hours onto the hour. Eg. 2 + 12 = 14 so it will be 14:45.pm

b. The length of time between 11:45am and 2:45pm is 3 hours.

I don't know what c is sorry.

Hope that helps. x

8 0

2 years ago

Divide. Show your work. (6x^4-5x^3+6x^2)/2x^2

serg [7]

We can do like we did before, distribute the denominator,

$\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3$

6 0

3 years ago

A Kroger's shopper bought a total of 8 pounds of

andreev551 [17]

Answer: 5 pounds

Step-by-step explanation: because you have to do 0.45 times 5 = 2.25 and then you know that 1.29 times 3 = 3.87 so you add 3.87 + 2.25 and u get 6.12

4 0

3 years ago

Points J and K lie in plane H.

Vlad [161]

Answer: 1

Step-by-step explanation:

From the given picture, it can be seen that there is a plane H on which two pints J and K are located.

One of the Axiom in Euclid's geometry says that "Through any given two points X and Y, only one and only one line can be drawn "

Therefore by Axiom in Euclid's geometry , for the given points J and K in plane H , only one line can be drawn through points J and K.

6 0

3 years ago

Read 2 more answers

I need to know I'm not sure if it is but I think it's not a function​

I need to know I'm not sure if it is but I think it's not a function