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Andre45 [30]
3 years ago
7

Write digit(s) can be in the ones place of a number that has 5 as a factor

Mathematics
1 answer:
kotykmax [81]3 years ago
5 0
5
5 is a factor of 5
I am typing to reach the word count
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120÷[17-{15-3(8-2)}]​
vodomira [7]

Answer:

the ans has to be 6.........

5 0
2 years ago
A shoebox is covered with packing paper before being shipped. The paper cost $0.02 per square inch. How much will it cost to cov
Yuliya22 [10]

It will cost about $0.72 for three pair of shoes assuming shoe box is rectangular shape having 12 square inches of packing paper.

Step-by-step explanation:

  • Assuming a shoe box rectangle in shape and the same size is required.
  • Length of rectangle box assuming to be 4 inches.
  • Width of rectangle box assuming to be 3 inches.
  • as we know area of rectangle is Length * Breath(Width) .
  • 12 square inches is the total packing paper required for each box.
  • To cover cost of three pairs of shoes $0.02 per square inch.
  • Each box would cost about 12 square inches * 0.02 pr square inches.
  • 0.24 square inches of packing paper will be required.
  • let three pairs of shoes be x
  • Total pairs of shoes would be= (12 * 0.02)*x
  • Answer would be for 3 pairs of shoes = 0.24*3 = 0.72 square inches.

3 0
2 years ago
Write 4.14 in a fractional notation ?
tatiyna
If it's in a fraction you want it it's 207/50 irregular
And 4 7/50 as a mixed fraction
3 0
3 years ago
If anyone can help me to write recursive and explicit definition for this sequence I'm giving extra points!!
KengaRu [80]

Step-by-step explanation:

Each term is 2 more than the previous term, and the first term is 12, so the recursive formula is:

a_{n}=a_{n-1}+2, a_{1}=12

This is an arithmetic sequence, so the explicit formula is:

a_{n}=12+2(n-1)\\a_{n}=10+2n

The next three terms are 20, 22, 24.

8 0
2 years ago
F(x) = -4x(2)+ 12x – 9
kenny6666 [7]

For this case we have the following function:

f (x) = - 4x ^ 2 + 12x-9

y = 0 we have:

-4x ^ 2 + 12x-9 = 0

Where:

a = -4\\b = 12\\c = -9

By definition, the discriminant of a quadratic equation is given by:

d = b ^ 2-4 (a) (c)

d> 0: Two different real roots

d = 0: Two equal real roots

d: Two different complex roots

Substituting the values we have:

d = (12) ^ 2-4 (-4) (- 9)\\d = 144-144

d = 0

We have two equal real roots.

To find the intersections with the x axis, we do y = 0:

-4x ^ 2 + 12x-9 = 0

We apply the quadratic formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values we have:

x = \frac {-12 \pm \sqrt {12 ^ 2-4 (-4) (- 9)}} {2 (-4)}\\x = \frac {-12 \pm \sqrt {144-144}} {- 8}\\x = \frac {-12 \pm0} {- 8}\\x = \frac {-12} {- 8}\\x = \frac {3} {2}

The intersection with the x axis is(\frac {3} {2}, 0)

Answer:

d = 0

The intersection with the x axis is (\frac {3} {2}, 0)

5 0
3 years ago
Read 2 more answers
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