The given zeros are -5, -5, 1 + 2i.
Because complex zeros occur in conjugate pairs, the zeros are
-5, -5, 1 + 2i, 1 - 2i.
The polynomial is
f(x) = (x+5)²[x- (1+2i)][x -(1-2i)]
Note that
[x - (1+2i)][x - (1-2i)]
= x² - x(1 - 2i) - x(1+2i) + (1 - 4i²)
= x² - 2x +5
Therefore
f(x) = (x+5)²(x²-2x+5)
Answer: f(x) = (x+5)²(x²-2x+5)
The answer is the first option
Ans:
Not rational number include √2, π, e, and φ. The decimal expansion of an irrational number.
Answer:
D. The work shown above is correct, and may not be simplified further.
Step-by-step explanation:
If you add all the exponents of y in first line then we get
4+4+4+4+4+3=23
Which is same as the exponent in original problem.
So first line is good.
Since it is 4th root so each will turn into y when it moves out of the radical so final answer is correct.
Hence correct choice is "D. The work shown above is correct, and may not be simplified further." is the correct answer.