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3 years ago

Which operation can be applied to the tickets sold in order to find the number of dollars donated?

Mathematics

2 answers:

Mumz [18]3 years ago

8 0

I think it would be divide by 2

hichkok12 [17]3 years ago

6 0

Answer:

it is divide by 2

Step-by-step explanation:

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One number is 4 more than another, and their sum is 60. What is the smaller number?

ivanzaharov [21]

According to your question, there are 2 unknown numbers mentioned. Let the 2 unknown numbers be represented by the variables x & y, then x is considered to be one of the numbers being more than y by the addition of 4, .ie. x = 4 + y --- (1) The sum of the 2 numbers is 60, i.e. x + y = 60 --- (2) To find the smaller number, we solve eqn (1) & (2) using the concept of substitution, i.e. substitute 4 + y for x in eqn (2), i.e. 4 + y + y = 60 4 + 2y = 60 2y = 60 - 4 2y = 56 y = 28 ...Ans. Recall that x is more than y by 4, then 28 is the smaller number.

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3 years ago

Express ( x + 4 )∧2 as a trinomial in standard form.

mamaluj [8]

Answer: x²+8x+16

Step-by-step explanation:

(x+4)^2=(x+4)(x+4)

Now use distributive property to expand (x+4)(x+4):

(x+4)(x+4)=x²+4x+4x+4(4)

x²+4x+4x+4(4)=x²+8x+16

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3 years ago

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What is the answer to -x-2/-4=3x+6/2

denis23 [38]

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3 years ago

The slope of a line running through points (-3,-5) and (0, -3) is:

Luda [366]

The slope is 2/3 and the y intercept if you need it is -3

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3 years ago

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Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and

Naddika [18.5K]

Answer:

Using a 90% confidence level

A. A sample size of 68 should be used.

B. A sample size of 98 should be used.

Step-by-step explanation:

I think there was a small typing mistake and the confidence level was left out. I will use a 90% confidence level.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 72 seconds, what sample size should be used?

We have the standard deviation in minutes, so the margin of error should be in minutes.

72 seconds is 72/60 = 1.2 minutes.

So we need a sample size of n, and n is found when M = 1.2. We have that $\sigma = 6$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$1.2 = 1.645*\frac{6}{\sqrt{n}}$

$1.2\sqrt{n} = 6*1.645$

$\sqrt{n} = \frac{6*1.645}{1.2}$

$(\sqrt{n})^{2} = (\frac{6*1.645}{1.2})^{2}$

$n = 67.65$

Rounding up.

A sample size of 68 should be used.

B. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 1 minute, what sample size should be used?

Same logic as above, just use M = 1.

$M = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.645*\frac{6}{\sqrt{n}}$

$\sqrt{n} = 6*1.645$

$(\sqrt{n})^{2} = (6*1.645)^2$

$n = 97.42$

Rounding up

A sample size of 98 should be used.

3 0

3 years ago