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3 years ago

Apples 23 and orange 65 how many orange and apple has?

Mathematics

2 answers:

Vikentia [17]3 years ago

5 0

You would have to add 23 and 65 to get 88 apples and oranges

Andrews [41]3 years ago

4 0

All you do is add 23 and 65 to get your answer <span />

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Find the distance between the points given.<br><br> (-3, 2) and (9, -3)

g100num [7]

The distance will be given by the equation;
D= $\sqrt{( x_{1} - x_{2} )^{2} +( y_{1} - y_{2} )^{2} }$
D= $\sqrt{ (-3-9)^{2}+( 2--3)^{2} }$
D= $\sqrt{ (-12)^{2} + (5)^{2} }$
D= $\sqrt{169}$
D=13 units

8 0

3 years ago

A baker made 60 muffins for a cafe. By noon, 45% of muffins were sold. How many muffins were sold by noon?

Genrish500 [490]

27

60÷100 =0.6
0.6×45 = 27

7 0

3 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

Frank's car is 12 feet long. Alex's car is 108 inches

kirill115 [55]

Answer:

21 feet

Step-by-step explanation:

108 inches / 12 = 9 feet.

9+12=21 feet

5 0

2 years ago

I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Basile [38]

Answer:

Step-by-step explanation:

6 0

2 years ago