Ask question

Ask question

All categories

vladimir1956 [14]

3 years ago

8

What is the are of the shaded region?

1 answer:

Eva8 [605]3 years ago

4 0

Shaded area = Area of circle - 2(area of one triangle)

The circle has radius 5 cm, so its area is $\pi 5^2=25\pi$

The triangle has a base of 6 cm. Two of its legs coincide with the radius of the circle, which means the height of the triangle must be 5 - 1 = 4 cm. So one triangle's area would be $\dfrac12\times6\times4=12$ .

Shaded area = $25\pi-2(12)=25\pi-24$ .

You might be interested in

Del ray can run 20 1/2 miles in 2 1/4 hours. How many miles per hour can he run?

emmasim [6.3K]

$20 \frac{1}{2} :2 \frac{1}{4} = \frac{41}{2}: \frac{9}{4}= \frac{41}{2}* \frac{4}{9} =\frac{82}{9} = 9 \frac{1}{9} \ \ \text{miles per hour}$

5 0

3 years ago

21 devided by 1.2<br> (Explained)

rewona [7]

The answer would be 17.(

7 0

3 years ago

Read 2 more answers

In the following equation y = 2x + 3, what value represents the growth?<br> Group of answer choices

iogann1982 [59]

Answer:

isn't it 2x?

Step-by-step explanation:

4 0

3 years ago

Solve equation, check for extraneous solutions

fiasKO [112]

Start with

$1=\dfrac{1}{n^2}+\dfrac{n^2-4n-5}{3n^2}$

We observe that both fractions are not defined if $n=0$ . So, we will assume $n \neq 0$ .

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

$1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}$

We multiply both sides by $3n^2$ :

$n^2-4n-2=3n^2$

We move everything to one side and solve the quadratic equation:

$2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1$

We check the solution:

$1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0$

which is true

8 0

3 years ago

Given: ∠ABC ≅ ∠DEF and ∠GHI ≅ ∠DEF Prove: m∠ABC = m∠GHI We are given that angle ABC and are congruent, and that angle GHI and an

evablogger [386]

1. Angle DEF

2. Definition of congruent angles

3. The measure of angle GHI

6 0

4 years ago