Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =

Answer:
W = 2.5d + 62
Step-by-step explanation:
The calf weighed 62 pounds when they were born. This gives us a base of 62 pounds - the calf cannot weigh less than 62 pounds and it does on day 0. On each day , the calf gains 2.5 pounds. We can times the number to days by 2.5 to get the gain from day 0. We can add these two values together to get the total current weight of the calf.
Answer:
60.1
Step-by-step explanation:
Just get 72.60 and subtract 12.50
We know that 60 minutes = 1 hour and 1 mile = 5280 feet. We just need to multiply and simplify:
651 miles/hour = 651 *5280/60 feet/minutes = 651*88 feet/minutes = 57288 feet/minutes
Answer:
4 units
Step-by-step explanation:
CAB and EAD are similar triangles with sides in the ratio 2:1
ED = ½ AB
½(8)
4