Find A cup(B cap C) . A = \{1, 4, 6, 7\}; B = \{3, 4, 5\}; C = \{2, 4, 8\}; \{1, 4, 6, 7\} 4 } \{1, 2, 3, 4, 5, 6, 7, 8\}
Inessa05 [86]
The only common element between B and C is 4, so B ∩ C = {4}.
4 is also already contained in A, so B ∩ C is a subset of A, and thus
A U (B ∩ C) = A = {1, 4, 6, 7}
C is the answer................
Add 6.5 to both sides
D=-0.7
A
3 + 3/4x > = 15
3/4x > = 15 - 3
3/4x > = 12
x > = 12 / (3/4)
x > = 12 * 4/3
x > = 48/3 = 16 sessions <==
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-p - 4p > -10
-5p > -10
p < -10/-5
p < 2 <===
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-3 - 6(4x + 6) > = 9
-3 - 24x - 36 > = 9
-24x - 39 > = 9
-24x > = 9 + 39
-24x > = 48
x < = -48/24
x < = -2 <===
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2x - 2 > = 10
2x > = 10 + 2
2x > = 12
x > = 12/2
x > = 6........so ur solution set is {6,7}
