Simplify -3 (2+4k) + 7 (2k -2)

Mathematics

2 answers:

rusak2 [61]2 years ago

8 0

Answer: 2k - 20

Step-by-step explanation:

fenix001 [56]2 years ago

6 0

Answer:

Step-by-step explanation:

-6-12k+14k-14

-6-14-12k+14k

-20+2k

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r-ruslan [8.4K]

Answer:

Not quite sure what you're meant to solve for, but my solution is below.

Step-by-step explanation:

The square root of a value squared is the absolute value of that value, because squaring removes all negatives. Therefore:

$\sqrt{(y+2)^2}=c$

$\mid y+2\mid=c$

$\mid y\mid =c-2$

Hope this helps!

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2 years ago

Read 2 more answers

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$