Suppose that of 1400 students, 550 take Spanish, 700 take biology, and 400 take both
1 answer:
Answer:
<u> </u>
Explanation:
<u>1. Call A the event of selecting a student who takes Spanish and P(A) the corresponding probability: </u>
P(A) = number of students who take Spanish / number of students
P(A) = 550 / 1400 = 11/28
<u>2. Call B the event of selecting a student who takes biology and P(B) the corresponding probability: </u>
P(B) = number of students who take biology / number of students
<u> </u>
<u>3. The joint probability, P(A∩B), is the probability that a student takes Spanish and biology: </u>
P(A∩B) = number of students that take both Spanish and biology / number of students
<u>4. By the properties of probabilities, the probability of the event A or B is: </u>
P (A or B) = P (A∪B) = P(A) + P(B) - P(A∩B)
P(A or B) = 11/28 + 1/2 - 2/7 = (11 + 14 - 8) / 28 = 17/28
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