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maria [59]
3 years ago
5

Based on a​ poll, 60​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is

the probability that among four randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to​ respond? The probability that at least one of them is careful about personal information is
Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

The probability that at least one of them is careful about personal information is 0.9744.

If the survey subjects volunteered to​ respond, then this a voluntary sampling and the estimated probability p may be biased, as only the people interested in the topic participate.

Given the subject of the survey, it is estimated that the ones who answered the survey are more careful about personal information and then the propability p is biased to a higher level than it should be if the sample was random.

Step-by-step explanation:

We can model this with a random variable, with sample size n=4 and probability of success p=0.6.

The probability that k individuals are more careful about personal information when using a public​ Wi-Fi hotspot in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{4}{k}\cdot0.6^k\cdot0.4^{4-k}

We have to calculate the probability that 1 or more are more careful about personal information when using a public​ Wi-Fi hotspot. This can be calculated as:

P(x\geq1)=1-P(x=0)\\\\\\P(x=0)=\dbinom{4}{0}\cdot0.6^{0}\cdot0.4^{4}=1\cdot1\cdot0.0256=0.0256\\\\\\P(x\geq1)=1-0.0256=0.9744

The probability that 1 or more individuals in the sample are more careful about personal information when using a public​ Wi-Fi hotspot is 0.9744.

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M-N= {a,d}

Step-by-step explanation:

subtract the common elements

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What does y equal? ​
tensa zangetsu [6.8K]

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y=-4x+17

Step-by-step explanation:

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2 years ago
A ball will be drawn from the bag containing 20 balls numbered one through 20 if each ball is equally likely to be drawn what is
son4ous [18]

Answer:

3/5

Step-by-step explanation:

There are 20 balls, numbered 1 through 20.

Of these, 10 are even, 4 are less than five, and 2 are both even and less than 5.

So the probability is:

P(even or <5) = P(even) + P(<5) − P(even and <5)

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5 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
Answer this with a fraction:
Neporo4naja [7]
Exact form 27/4
decimal form 6.75
mixed number form 6(3/4)
6 0
2 years ago
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