Answer:
1.) Yes
2.) Yes
Step-by-step explanation:
Given that
n = k(k + 7)
If k is a positive integer and n = k(k + 7), is n divisible by 6 ?
(1) k is odd. Yes.
Let assume that k = 3
Then, n = 3(3 + 7)
n = 3 × 10
n = 30.
30 is divisible by 6.
(2) When k is divided by 3, the remainder is 2. That is,
Let k = 5
Then,
5/3 = 1 remainder 2
Substitute k into the equation
n = k(k + 7)
n = 5(5 + 7)
n = 5 × 12
n = 60
And 60 is divisible by 6.
Therefore, the answer to both questions is Yes.
I'll help you but I;m not just going to give you the answer
Answer:
(3, 2), (6, 4)
Step-by-step explanation:
Since one end (A) of the segment AB is at the origin, the required points will be 1/3 and 2/3 of the coordinates of B:
(1/3)(9, 6) = (3, 2)
(2/3)(9, 6) = (6, 4)
<span>(4x ÷ 2) - 9y
is difference of two terms.</span>
Answer:
We have the following equation: y = 36 - x. And we need to find which of the following points belong to the graph:
If any of the points belong to the equation, then the equality will be met.
Then:
7 = 36 - (-13)
7 = 36 + 13
7 = 49 ❌
1 = 36 - (-35)
1 = 71❌
5 = 36 - 11
5 = 25 ❌
3 = 36 - 27
3 = 9 ❌
None of the points belong to the graph. Therefore, all points are NOT on the grah of p(x) = 36 - x.
