Answer:
Option b is the correct answer for the above question.
Explanation:
- The mystery function is a recursive function that calls for the two times when the user passes 38 on the argument.
- The first value is 38 and the second value is 2 for which that function is called.
- When the value 38 is passed, then again 2 is passed because of the "mystery (n % 3);" statement.
- This statement holds by the if condition which gives the true when the argument value is greater than 2.
- Hence for the 2 value the if condition will not true and the function is not called again.
- Then the 38/3 and 2/3 are printed whose value is 12 0, but it will print 0 12 because of the recursive function.
- Hence option b is the correct answer while the other is not because other options does not states the output of this program.
Answer:
Sequential
Explanation:
Based on the information provided within the question it can be said that the search algorithm that is being described in this scenario is a Sequential algorithm. This is because sequential programming focuses on programming (or in this case searching for) a result by doing one step at a time as opposed to various functions running simultaneously.
The diagram of the of a ten-node network that uses ten routers is given in the image attached.
<h3>What is a node in a network?</h3>
A network node is known to be be seen as the kind of connection point that is seen amidst some network devices such as routers, printers, etc.
Note that they are known to often receive and send data from one network or endpoint to another.
Therefore, The diagram of the of a ten-node network that uses ten routers is given in the image attached.
Learn more about routers from
brainly.com/question/24812743
#SPJ1
Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
string email,username,host;//strings to store email,username,hostname..
cout<<"Enter the email address "<<endl;
cin>>email;//taking input of email address..
bool flag=1;
for(int i=0;i<email.length();i++)//iterating over the string email..
{
if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.
{
flag=0;
continue;
}
if(flag==1)//add to username if flag is 1.
{
username+=email[i];
}
else//add tom host..
host+=email[i];
}
cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..
return 0;
}
Explanation:
I have taken three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.
The instructions that he microprocessor can execute each
second if the assembly line is present will be depending on the workload and
the architecture’s core because it is all depending on the speed of the CPU and
the multiplier that it acquires.