Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Answer:The system partition and the boot partition are computing terms for disk partitions of a hard disk drive or solid-state drive that must exist and be properly configured for a computer to operate. There are two different definitions for these terms: the common definition and the Microsoft definition. - Wikipedia.
Explanation:
To prevent theft of account information, identity theft, money, important passwords, and personal information.
Hope it helps ❤️
(python) Answer:
sum = 0
for i in range 1 to 101:
if i modulo 2 == 0:
sum += i
print(sum)
Explanation:
first we declare the sum variable
then go through all numbers 1 through 100 (range 1 to 101 because python range does not include the last number - if we did 1 to 100 it would look at 1 to 99)
if the number is even (divide by 2, check if there's a remainder, if not it's even and we will add the number to the sum
finally print the sum
Of course it is. No one's going to come and track you down for downloading an image from the internet.
In many cases, images may be under some sort of ownership license like copyright, preventing you from modifying and distributing the image as your own. But again, so many people do it anyway, because no one is going to come knocking on your door because you downloaded an image from the internet.
