First we need to write the factors of the polynomial. In order for 1, 4, and -3 to be roots, they need to be the x values that make the polynomial equal 0.
(x - 1) = 0
That would be the factor for x = 1 because when we plug 1 in for x we get 1 - 1 which equals 0.
Multiply all the factors together.
(x-1)(x-4)(x+3)=0
Now FOIL.

Answer:
Step-by-step explanation:
x+15+x+115+90=380 degree(sum of interior angles of four angles is 360 degree)
2x+220=360
2x=360-220
x=140/2
x=70 degree
Answer:
B
Step-by-step explanation:
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 