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ale4655 [162]
3 years ago
7

What is the value of cosθ given that (−2, 9) is a point on the terminal side of θ ? 985√85

Mathematics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

-2√85 / 85

Step-by-step explanation:


Vladimir79 [104]3 years ago
5 0

Answer:

cos\theta=\frac{-2}{\sqrt{85} }

Step-by-step explanation:

Let's call <em>r </em>the distance form the origin to the point (-2,9), this distance is related with cos\theta with the expression

x=rcos\theta\\cos\theta=\frac{x}{r}

So, we have to find <em>r </em>with the formula of distance and the given point:

r=\sqrt{x^{2}+y^{2}}=\sqrt{(-2)^{2}+(9)^{2} }\\r=\sqrt{4+81}=\sqrt{85}

Now, replacing on the first relation, we have

cos\theta=\frac{-2}{\sqrt{85} }

Therefore, the answer is

cos\theta=\frac{-2}{\sqrt{85} }

PD: choices were written wrong.

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Which of the following is not a way to represent the solution of the inequality 8x – (5x + 4) 2-31?
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7 0
3 years ago
I need help with this 8
zubka84 [21]

The complete proof for the given parallelogram is given in the image attached below.

<h3>What is a Parallelogram?</h3>

A parallelogram is a quadrilateral whose opposite sides are parallel and also congruent to each other.

The complete proof would be as shown below:

1. ABCD is a parallelogram [given]

2. AB║CD [Definition of parallelogram]

3. ∠1 ≅ ∠2, ∠3 ≅ ∠4 [alternate interior angles theorem]

4. AB ≅ CD [Definition of parallelogram]

5.  ΔABE ≅ ΔCDE [ASA]

6. AE ≅ CE, BE ≅ DE [CPCTC]

7. AC and BD bisects each other at E [definition of segment bisector]

Learn more about parallelogram on:

brainly.com/question/3050890

#SPJ1

6 0
2 years ago
PLease tell me how to do it that will give you brainliest
Evgen [1.6K]

Answer: Table H would be the correct answer;

The rule of a function is that for each x-value given there can't be more than 1 y-value

<u>In Table F:</u>

x = -13, then y = -2

x = -13, then y = 0

x = -13, then y = 5

x = -13, then y = 7

For the x-value -13, there are 4 different y-values, so <em>it's not a function.</em>

<u>In Table G:</u>

x = -6, then y = 3

x = -1, then y = -1

x = -1, then y = 5

x = 10, then y = -9

For the x-value -1, there are 2 different y-values, hence <em>this isn't a function.</em>

<u>In Table H:</u>

x = 1, then y = 4

x = 3, then y = 4

x = 7, then y = 4

x = 12, then y = 4

For each x-value, there is only 1 y-value, so <em>this is a function.</em>

<u>In table J:</u>

x = -9, then y = -7

x = -2, then y = -5

x = 0, then y = 0

x = 0, then y = 6

For the x-value 0, there are 2 different y-value therefore <em>this isn't a function</em>

Hope this helps!

6 0
3 years ago
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