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ale4655 [162]
3 years ago
7

What is the value of cosθ given that (−2, 9) is a point on the terminal side of θ ? 985√85

Mathematics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

-2√85 / 85

Step-by-step explanation:


Vladimir79 [104]3 years ago
5 0

Answer:

cos\theta=\frac{-2}{\sqrt{85} }

Step-by-step explanation:

Let's call <em>r </em>the distance form the origin to the point (-2,9), this distance is related with cos\theta with the expression

x=rcos\theta\\cos\theta=\frac{x}{r}

So, we have to find <em>r </em>with the formula of distance and the given point:

r=\sqrt{x^{2}+y^{2}}=\sqrt{(-2)^{2}+(9)^{2} }\\r=\sqrt{4+81}=\sqrt{85}

Now, replacing on the first relation, we have

cos\theta=\frac{-2}{\sqrt{85} }

Therefore, the answer is

cos\theta=\frac{-2}{\sqrt{85} }

PD: choices were written wrong.

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Answer:

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Step-by-step explanation:

150/3=50

220/4=55

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3 years ago
The ratio of the perimeter of two similar polygons is 5:7. The area of the smaller polygon is 30 sq. cm. Find the area of the la
Debora [2.8K]

Answer:

42sq

Step-by-step explanation:

       5:7

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3 years ago
Sum of x and it’s square is equal to y times z
ludmilkaskok [199]

The algebraic representation of the statement is x + x² - yz = 0

<h3>What are algebraic expressions?</h3>

Algebraic expressions brings the idea of creating or expressing numbers using letters or alphabets without specifying their actual values.

From the information given , we have that;

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  • Equal to y × z

Now, let's equate the expressions;

x + x² = y × z

x + x ² = yz

Let's make into quadratic form

x + x² - yz = 0

Thus, the algebraic representation of the statement is x + x² - yz = 0

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2 years ago
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Lina20 [59]
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7 0
3 years ago
Read 2 more answers
Z−4/9−1/3=5/9 Enter your answer as a fraction in simplest form in the box. z =
aleksklad [387]

Answer:

z = 4/3 or 1 1/3

Step-by-step explanation:

z−4/9−1/3=5/9

Change 1/3 to have a denominator of 9

1/3 *3/3 = 3/9

z−4/9−3/9=5/9

Combine like terms

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Add 7/9 to each side

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z = 12/9

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or as a mixed number

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7 0
3 years ago
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