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ale4655 [162]
2 years ago
7

What is the value of cosθ given that (−2, 9) is a point on the terminal side of θ ? 985√85

Mathematics
2 answers:
MAVERICK [17]2 years ago
6 0

Answer:

-2√85 / 85

Step-by-step explanation:


Vladimir79 [104]2 years ago
5 0

Answer:

cos\theta=\frac{-2}{\sqrt{85} }

Step-by-step explanation:

Let's call <em>r </em>the distance form the origin to the point (-2,9), this distance is related with cos\theta with the expression

x=rcos\theta\\cos\theta=\frac{x}{r}

So, we have to find <em>r </em>with the formula of distance and the given point:

r=\sqrt{x^{2}+y^{2}}=\sqrt{(-2)^{2}+(9)^{2} }\\r=\sqrt{4+81}=\sqrt{85}

Now, replacing on the first relation, we have

cos\theta=\frac{-2}{\sqrt{85} }

Therefore, the answer is

cos\theta=\frac{-2}{\sqrt{85} }

PD: choices were written wrong.

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Answer:

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Step-by-step explanation:

Use the distributive property.

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Answer: 3x + 12

3 0
2 years ago
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garik1379 [7]

Answer:

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3 years ago
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GrogVix [38]

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2 years ago
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2 years ago
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