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Irina-Kira [14]
3 years ago
10

Compared to diagrams and equations, tables are always the best way to find the value of a variable?

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

It is false. Hope you pass! :)

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S_A_V [24]

Answer:

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Plsss help me anybody pls my school is almost done pls helppppp
RideAnS [48]

Answer:

(-3,-13) (-10,-6) (4,-6) (-3,1)

(-8,-12) and (-1,-12)

Step-by-step explanation:

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3 years ago
The average of Johnny's two tests is a 92. What must he get on a 3rd test to raise his average to a 94?
eduard
Let's start by writing an equation for this. So in overall, there will be 3 tests. Therefore, If the first two average to 92, then the third plus those two individual scores divided by 3 will need to equal 94. Lets call the new score x.
(92 x 2 + x) / 3 = 94
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Johnny will need to get a 98 on the 3rd test to raise his average to exactly 94.
I hope this helps :-)
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3 years ago
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WILL GIVE BRAINLIEST AND 30 POINTS!
mafiozo [28]

Answer:

14

Step-by-step explanation:

f(x) =  {x}^{2}  + 10 \\  \therefore \: f(2) =  {2}^{2}  + 10 \\ \therefore \: f(2) =  4  + 10 \\ \therefore \: f(2) =  14 \\  \\ g(x) =  |x|  \\ \therefore \:g(2) =  |2|  \\ \therefore \:g(2) =  2  \\  \\  f(2) + g(2) = 14 + 2 \\  \red{ \bold{(f + g)(2) = 14}}

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3 years ago
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Determine whether the alternating series E (-1)^n+1 (n/8)^n converges or diverges. Choose the correct answer below​ and, if​ nec
RUDIKE [14]

Answer:

C

Step-by-step explanation:

Solution:-

- The Alternate series test is applicable for alternating series with has terms summed and subtracted alternatively and takes the form of:

       

                                   ∑ an

Were,

                                a_n = ( -1 ) ^(^n^+^1^) b_n

- Where, {  bn } > 0 for all n. Then if the following conditions are met:

1. Lim ( n -> ∞ ) { b_n } = 0

2. b ( n + 1 )  < bn  .... bn is a decreasing function.

Conclusion:- The series { ∑ an } is convergent.

- The following series is given as follows:

                                ∑  ( - 1 )^(^n^+^1^) (\frac{n}{8} )^n

Where,

                               b_n = (\frac{n}{8} )^n

1 . We will first test whether the sequence { bn } is decreasing or not. Hence,

                              b_n_+_1 - b_n < 0\\\\(\frac{n+1}{8})^(^n^+^1^) - (\frac{n}{8})^n\\\\(\frac{n}{8})^n ( \frac{n-7}{8} ) \\\\

We see that for n = 1 , 2 , 3 ... 6 the sequence { b_n } is decreasing; however, for n ≥ 7 the series increases. The condition is not met for all values of ( n ). Hence, the Alternating series test conditions are not satisfied.

We will now apply the root test that states that a series given in the following format:

                               ∑ an

- The limit of the following sequence { an } is a constant ( C ).

                               C = Lim ( n - > inf ) [ a_n ] ^\frac{1}{n} \\\\

1. C < 1 , The series converges

2.C > 1 , The series diverges

3. C = 1 , test is inconclusive

- We will compute the limit specified by the test as follows:

                          Lim ( n - >inf ) = [ (\frac{n}{8})^n ]^\frac{1}{n}   \\\\Lim ( n - >inf ) = [ (\frac{n}{8}) ] = inf   \\\\

- Here, the value of C = +∞ > 1. As per the Root test limit conditions we see that the series { ∑ an } diverges.

Note: Failing the conditions of Alternating Series test does not necessarily means the series diverges. As the test only implies the conditions of "convergence" and is quiet of about "divergence". Hence, we usually resort to other tests like { Ratio, Root or p-series tests for the complete picture }.

8 0
3 years ago
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