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Nata [24]
3 years ago
15

An auditorium has 30 rows with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth. How many seat

s are in the auditorium?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

1170

Step-by-step explanation:

start with 10 and add 2 to each row. Then add each number up when you have 30 numbers.

10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44, 46,48,

50,52,54,56,58,60,62,64,66,68.

You get 1170 seats total.

I know there is a type of equation that can be used but I wanted to be 1000 percent sure of my answer to you to be correct.

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We first calculate the z-score corresponding to x = 1075 kWh. Given the mean of 1050 kWh, SD of 218 kWh, and sample size of n = 50, the formula for z is:
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serg [7]
The answer is 27.6
angle version of the law of cosines:

cos(C) = (a^2 + b^2 − c^2)/2ab 

cos(A) = (b^2 + c^2 − a^2)/2bc

cos(B) = (c^2 + a^2 − b^2)/2ca


cos A = (b^2 + c^2 − a^2) / 2bc
cos A = (10^2+20^2-14<span>^2)/200
cos A = (100+400-196)/200
cos A = (500-196)/200
cos A = (304)/200
cos A = (1.52)
A = cos</span><span>^-1(1.52) = 40.54 degrees

cos B = (c</span>^2+a^2-b<span>^2)/2ca
cos B = (20</span>^2+14^2-10<span>^2)/280
cos B = (400+196-100)/280
cos B = (496)/280
cos B </span>≈ 1.77
B = cos<span>^-1(1.77) = 27.66 degrees

we have two methods left to find the measure of angle C:
method 1 :
cos C = (a</span>^2+b^2-c<span>^2)/2ab
cos C = (14</span>^2+10^2-20<span>^2)/140
cos C = (196+100-400)/140
cos C = (-104)/140
cos C </span>≈ -0.74

C = cos<span>^-1(-0.74) = 111.8 degrees

method 2: 40.54+27.66 = 68.2
180-68.2=111.8

The measure of angle A: 40.54
The measure of angle B: 27.66
The measure of angle C: 111.8



</span>
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Answer:

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