Find the value of unknown side

Mathematics

2 answers:

galben [10]2 years ago

8 0

Answer:

hope this help you

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S_A_V [24]2 years ago

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Answer:

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If line q bisects EG at point T, and if ET= 1/3 x and TG= x-2, then find EG

kvasek [131]

Answer:

EG = 2 units

Step-by-step explanation:

Given that line q bisects EG at T , then

ET = TG ( substitute values )

$\frac{1}{3}$ x = x - 2 ( multiply through by 3 to clear the fraction )

x = 3x - 6 ( subtract x from both sides )

0 = 2x - 6 ( add 6 to both sides )

6 = 2x ( divide both sides by 2 )

3 = x

Then

ET = $\frac{1}{3}$ x = $\frac{1}{3}$ × 3 = 1

TG = x - 2 = 3 - 2 = 1

Thus

EG = ET + TG = 1 + 1 = 2 units

8 0

2 years ago

Read 2 more answers

Show that <br><br> 4(m + 7) + (m + 3)^2 = (m + 3)(m + 7) + 16

anygoal [31]

Step-by-step explanation:

$4(m+7)+(m+3)^2=(m+3)(m+7)+16\\\\L_S=4(m+7)+(m+3)^2\\\\\text{use the distributive property}:a(b+c)=ab+ac\\\text{and formula}:\ (a+b)^2=a^2+2ab+b^2\\\\L_S=(4)(m)+(4)(7)+m^2+2(m)(3)+3^2\\\\L_S=4m+28+m^2+6m+9\qquad\text{combine like terms}\\\\L_S=m^2+(4m+6m)+(28+9)\\\\L_S=m^2+10m+37$

$R_S=(m+3)(m+7)+16\\\\\text{use FOIL}:(a+b)(c+d)=ac+ad+bc+bd\\\\R_S=(m)(m)+(m)(7)+(3)(m)+(3)(7)+16\\\\R_S=m^2+7m+3m+21+16\qquad\text{combine like terms}\\\\R_S=m^2+(7m+3m)+(21+16)\\\\R_S=m^2+10m+37\\\\\boxed{L_S=R_S}$