The required function with maximum value 3 and x and y-intercepts π/2 and 3 respectively is y=-3cos(x)
<h3>What is a function?</h3>
A function is a rule that relates two variables.
Let us check the x-intercept, y-intercept, and maximum value for each function.
1)y =-3Sin(x)
for x-intercept put y=0
0 = -3Sin(x)
Sin(x) =0
x=0
for y-intercept put x=0
y=-3Sin0
y=0
The maximum value of the given function =the lower limit of the range of -3Sin(x) i.e. 3
Similarly, for y = -3cos(x)
x-intercept =π/2
y-intercept = 3
Maximum value of function = lower limit of the range of 3cos(x) i.e. 3
Therefore, the required function with maximum value 3 and x and y-intercepts π/2 and 3 respectively is y=-3cos(x)
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Answer and Step-by-step explanation:
Given
ax + by = c
qx + ry = s
(a) the equation has no solutions if a/q = b/r ≠ c/s, when this happens, we say the system of equations has no solution. For example
x + y = 3
x + y = 5
Subtracting first equation from the second we have:
0 = 2 which is impossible.
(b) the equations have infinite solutions if a/q = b/r = c/s, for example
x + y = 2
x + y = 2
Subtracting the first equation from the second we have
0 = 0, since this is always true, then it has infinite solutions.
(c) the equations have unique solutions if a/q ≠ b/r, for example
x + y = 2
x – y = 1
Adding the first and second equation we have
2x = 3, we can get x from here and definitely y, so we have just one solution.
150. Divide 5000 by 100 and you get 50. Multiply 3 by 50 and you get 150.
Answer:
4/5
Step-by-step explanation:
1+3=4
