Possible dimension of a box with a volume of 100 cubic cm
10 x 10 x 1 = 100
10 x 5 x 2 = 100
5 x 5 x 4 = 100
Surface area:
10 x 10 x 1 dimensions:
10 x 10 = 100 x 2 = 200 sq.cm
10 x 1 = 10 x 4 = 40 sq. cm
240 sq. cm * $0.05 / 100 sq.cm = $0.12 per box
0.12 per box * 100 boxes = $12
10 x 5 x 2 dimension
10 x 5 = 50 x 2 = 100 sq. cm
10 x 2 = 20 x 2 = 40 sq. cm
5 x 2 = 10 x 2 = 20 sq. cm
160 sq. cm * $0.05/100 sq. cm = $0. 08 per box
0.08 per box * 100 boxes = $8
5 x 5 x 4 dimension
5 x 5 = 25 x 2 = 50 sq. cm
5 x 4 = 20 x 4 = 80 sq. cm
130 sq. cm * $0.05/100 sq. cm = $0.065 per box
0.065 per box * 100 boxes = $6.50
The best dimension to use to have the least cost to make 100 boxes is 5 x 5 x 4. It only costs $6.50 to make 100 boxes.
Y=1/2x -3 find the x coordinate of the point whose y
coordinate is 5
y = 5. Write the equation as:
1/2F2x - 3 = 5
multiply both sides by 2, and you have
x - 6 = 10
x = 10 + 6
x - 16
Check solution in original equation, replace x with 16
y = 1/2F2(16) - 3
y = 8 - 3
y = 5
Answer:
144
Step-by-step explanation:
Length of 1 side is 12 so area is 12*12
Answer:
m<RPQ = 22°
Step-by-step explanation:
Given:
m<SRQ = 90°
PS = PQ
m<SQR = 46°
Required:
m<RPQ
Solution:
m<SQR + m<SRQ + m<RSQ = 180°
Substitute
46° + 90° + m<RSQ = 180°
m<RSQ = 180° - 136°
m<RSQ = 44°
Find m<PSQ:
m<PSQ = 180° - m<RSQ (Angles on a straight line
m<PSQ = 180° - 44° (Substitution)
m<PSQ = 136°
Find m<RPQ:
∆QSP is an isosceles triangle with two equal base angles. Therefore:
m<RPQ = ½(180° - 136°)
m<RPQ = 22°
What? I don’t understand what you’re asking.
