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victus00 [196]
3 years ago
11

Jacob and his team plays third in this years Ultimate frisbee tournament the o official frisbee be used in the tournament had a

diameter of 10 inches what was the approximate circumference of the frisbee
Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0
The circumference is 31.4
kow [346]3 years ago
6 0
Radius is half of diameter, so radius is 5. The formula for circumference is 2 * pi * radius, so 10pi, or 31.45.
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What is a million times all the numbers in the world
kozerog [31]
Well, there isn’t really an end for numbers...

However; The biggest number referred to regularly is a googolplex (10googol), which works out as 1010^100. That isn’t the end to numbers but it is a huge one. We will replace that with ‘all the numbers in the world’.

106 is the exponent equivalent to 1 million

So your question would be:
106 x 1010^100 =

However I don’t believe there is a calculator that large.
7 0
3 years ago
Hello can anyone give me the full answer to this step by step?
Andre45 [30]

Answer:

1. f = 16 degrees

2. h = 10 degrees

Step-by-step explanation:

1. f = (180 - 67+46 - 4) / 4

2. h = (180 - 60 + 90) / 3

5 0
2 years ago
Read 2 more answers
The table shows the American League batting champions for the years 1999–2003. The sum of these five batting averages is 1.754.
fgiga [73]
The answer is <span>A. .357 + .372 + .350 + .349 + x = 1.754; .326 
</span>
x1 - average of <span>1999 Nomar Garciaparra Boston
</span>x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of <span>2001 Ichiro Suzuki Seattle 
</span>x4 - average of Manny Ramirez Boston  
x - average of <span>2003 Bill Mueller Boston 

</span><span>The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754

From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?

<u>0.357 + 0.372 + 0.350 + 0.349 + x = 1.754</u>

1.428 + x = 1.754
x = 1.754 - 1.428
<u>x = 0.326</u></span>
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=
KiRa [710]
e ^{2x} = ln5

Solve for the real domain

e ^{2x} = ln(5)

if f(x) =g(x), then ln(f(x))= ln(g(x))

ln(e ^{2x} ) = ln(ln(5))

Solve : <span>ln(e ^{2x} ) = ln(ln(5))
</span>
use the logarithmic definition :

ln(e^{f(x)} ) = f(x)

ln(e^{2x} ) = 2x

2x=ln(ln(5))

Divide both sides by 2 :

\frac{2x}{2} = \frac{ln(ln(5))}{2}

x= \frac{ln(ln(5))}{2}

hope this helps!

8 0
3 years ago
BRAINLIEST + 10 + POINTS!!
ikadub [295]

Answer:

Step-by-step explanation:

6 0
3 years ago
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