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Veseljchak [2.6K]
3 years ago
13

What is the surface area of 20in 7in and 15in​

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

1090in squared

Step-by-step explanation:

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Find the area of this shape.
mart [117]

Answer:

shape AREA= 35cm^2

Step-by-step explanation:

you should know that this shape is a combination of triangle and trapezoid. therefore you have to find the area of each shape and add them.

A=h/2(b1 + b2) for trapezoid

A=2/2((4+4)+4)

A=1*12

A=12cm^2

A=bh/2. for TRIANGLE

A=1/2((4+4)*5.75)

A=1/2(46)

A=23cm^2

shape AREA= triangle AREA + trapezoid AREA

shape AREA=12cm^2 + 23cm^2

shape AREA= 35cm^2

5 0
3 years ago
-10 ➗-5/6<br><br><br> Solve this equation!
exis [7]

Answer:

12

Step-by-step explanation:

HOPE IT HELPS!!!!!!

8 0
3 years ago
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Find the area of the figure. If you need to use pi in your computation, approximate its value as 3.14. Round to the nearest hund
Firlakuza [10]
I find it easier to have a visual for when solving for shapes. You should solve for area of the semicircles by doing A=(3.14r^2)/2
Radius in this case is the base /2
In a Calculator that can be inputted as (3.14(4))/2

for this problem though I'm afraid that I need to know whether the height belongs to the figure as a whole or just regarding the rectangle.

If it is just the rectangle then we can do A=B*h
A= 4*5= 20
20 + semicircle
20 + 6.28
Total= 26.28
3 0
3 years ago
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Pedro bought a movie ticket for $9.50 and popcom por $4.35. He has $8.75 left
Olegator [25]

Answer:

He had $22.60

Step-by-step explanation:

$9.50 + $4.35 = 13.85 + 8.75 = $22.60

6 0
3 years ago
A construction worker drops a hammer from a height of 25 m.
Snezhnost [94]

Answer:

Time at which the hammer reaches the ground is 2.3 seconds.

Step-by-step explanation:

We are given the formula as, h(t)=-4.9t^2+v_{o}+h_{o}.

It is known that, when height i.e. h_{o}=25 meter, then velocity v_{o}=0 m/sec.

So, we get the formula as, h(t)=-4.9t^2+25.

Now, when the hammer hits the ground, the height h_{o}=0 meter.

Thus, we have,

h(t)=-4.9t^2+25

⇒ 0=-4.9t^2+25

⇒ 4.9t^2=25

⇒ t^2=5.1

i.e. t= ±2.3 sec

Since, time cannot be negative.

So, t= 2.3 sec

Hence, the time at which the hammer reaches the ground is 2.3 seconds.

4 0
3 years ago
Read 2 more answers
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