2 years ago

Y=2x^2+8x+1 find the vertex of the function below

Mathematics

1 answer:

katovenus [111]2 years ago

7 0

The answer would be Y= 2(x+2)^2-7

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3 years ago

Y=2x^2+8x+1 find the vertex of the function below ​

Y=2x^2+8x+1 find the vertex of the function below