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serg [7]
2 years ago
11

PLLLLEASE ASAP GUYS PLEASEE OMG

Mathematics
2 answers:
vovangra [49]2 years ago
7 0

Answer:

27/30

Step-by-step explanation:

9/10 x3 to both sides = 27/30

Ket [755]2 years ago
6 0

Answer:

\dfrac{27}{30}

Explanation:

In a normal fraction such as \frac{a}{b}, a is the numerator and b is the denominator.

Here the given fraction is \frac{9}{10}, to rewrite the fraction with a denominator of 30. <u>Multiply</u> both the numerator and denominator <u>by 3</u>.

\rightarrow \dfrac{9}{10}

\rightarrow \dfrac{9\:\times\:3}{10 \:\times \: 3}

\rightarrow \dfrac{27}{30}

Both the fractions are equivalent to each other.

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!
erastovalidia [21]

Answer:

B

Step-by-step explanation:

7 is the only number of those in the decimal form.

5 0
3 years ago
What fraction of the circle would 3 pieces represent?
UkoKoshka [18]

Answer:

3/4 would represent the shaded in parts of the circle

Step-by-step explanation:

I cannot give you an accurate answer seeing as you did not give much detail

4 0
3 years ago
Factor each polynomial completely. If you use a Special Pattern, identify which one you used.
VARVARA [1.3K]

Answer:

6,true 7,false 8,false 9,true 10,true

Step-by-step explanation:

8 0
3 years ago
Given f(x) = -6x - 1 and g(x) = x3, choose<br> the expression for fºg)(x).
Gelneren [198K]

Answer:

- 6x³ - 1

Step-by-step explanation:

Substitute x = g(x) into f(x), that is

(f ○ g)(x)

= f(x³ )

= - 6(x³) - 1

= - 6x³ - 1

4 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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