For part a, yes because each student is paying the same amount
For part c, each student is paying $15 to go
For part d, it's $1800
For part e, it would be 95 students
Answer:
the answer to this one is A.
Step-by-step explanation:
(37 1/2) /100
37.5/100
anything divided by 100 means you move the decimal point to the left two spaces
answer=0.375
Answer:
750
Step-by-step explanation:
Are / ?
Fraction?
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru