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3 years ago

6

Find the LCM of the pair of polynomials.

1 answer:

svet-max [94.6K]3 years ago

7 0

$2x^{2}-8x+8$

Factor the polynomial.

2( $x^{2}-4x+4$ )

2(x-2) $^{2}$

Factor the other Polynomial.

3 $x^{2}+27x-30$

$3(x^{2}+9x-10)$

$3(x+10)(x-1)$

This is your answer.

$6(x-2)^{2}(x+10)(x-1)$

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A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat.If the mixture is to be made from milk containing

3241004551 [841]

Answer:

<u>800 pints</u> of 5% butterfat and <u>200 pints</u> of 20% butterfat is needed.

Step-by-step explanation:

Given:

A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat.

If the mixture is to be made from milk containing 5% butterfat, and cream

containing 20% butterfat.

Now, to find the pints of each is needed.

Let the pints of 5% butterfat be $x.$

And the pints of 20% butterfat be $y.$

<em>So, the total pints of milk:</em>

$x+y=1000$

$x=1000-y$ ......(1)

<em>As, given:</em>

<em>1,000 pints of milk that contains 8% butterfat.</em>

<em>The mixture of milk containing 5% butterfat, and cream containing 20% butterfat.</em>

According to question:

$5(x)+20(y)=8(1000)$

$5x+20y=8000$

Substituting the value of $x$ from equation (1):

$5(1000-y)+20y=8000$

$5000-5y+20y=8000$

$5000+15y=8000$

<em>Subtracting both sides by 5000 we get:</em>

$15y=3000$

<em>Dividing both sides by 15 we get:</em>

$y=200.$

<em>The pints of 20% butterfat = 200 pints.</em>

Now, to get the pints of 5% butterfat we put the value of $y$ in equation (1):

$x=1000-y$

$x=1000-200$

$x=800.$

<em>The pints of 5% butterfat = 800 pints.</em>

Therefore, 800 pints of 5% butterfat and 200 pints of 20% butterfat is needed.

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Step-by-step explanation:

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