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kkurt [141]
3 years ago
11

The volume of a cube is 343 cm³ what is the surface area of the cube

Mathematics
2 answers:
blagie [28]3 years ago
5 0
6V^2/3
294
I used googles calculator home that helps
kkurt [141]3 years ago
5 0
Hello,
Volume of the cube=
s^3 where s represent side of the cube

Apply all the information that we had into this problem:
343=s^3
To find the side, cubic root it to get:
s=7 cm.
To find S.A=
s^2×6
=7^2×6
=49×6
=294 cm square. As a result, the surface area of the cube is 294 square cm. Hope it help!
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In PQRS, PR and QS intersect at T. What additional information is needed to conclude that PQRS is a rectangle
lora16 [44]
If it's congruent and similar
5 0
3 years ago
Solve 31-X + (2 x + 1)] = x - 1.
Kobotan [32]

Answer:

x = X + 33 (I am guessing "x" and "X" are not the same. "x" is a variable and "X" is a constant.)

Step-by-step explanation:

31 - X + (2x+1) = x - 1

or, 2x+1 = x - 1 - 31 + X

or, 2x - x = -1 -31 + X -1

or, x = -2 -31 + X

or, x = X - 33

6 0
2 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5 percent of these are defective.

This means that p = 0.05

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.0025 = 0.25% probability that both are defective

4 0
3 years ago
I WILL GIVE BRIANLIEST!!!!!!!!
attashe74 [19]

Answer:

a

Step-by-step explanation:

a

4 0
3 years ago
(4x3y3)3<br>me pueden ayudar​
Dominik [7]

Answer:

12x9y9

Step-by-step explanation:

( 4x3y3 ) 3

= 4x ⋅ 3 ⋅ 3y ⋅ 3 ⋅ 3 ⋅ 3

= 12x9y9

7 0
3 years ago
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