It is helpful to write them in different ways
some ways to write them are
1.fractions
2.decimals
3.squareroots (if applicable)
so it would be more helpful in an equation to leave 6/7 in fractional form if you are going to manipulate it more, because 0.857142857142... is much harder to keep track of than 6/7
and sometimes, they want a percent which is easier to convert to from decimal form than from fractinoal form so ex 0.857142857142...=85.7% vs 6/7 to percent
sometimes there will be square roots and they are easier if left like that ex
√2=1.4142135623...
it would be easier to leav it in square root
it depends on the equation you are trying to solve, because different forms have different pros and cons, some are easier to work with in a certain form but not in another, sometimes, you will need to change between multipule forms during the same problem
Answer: -29.3
Step-by-step explanation: -7y + 2x
-7(-6.3) + 2(-7.4) = -29.3
Answer:
Number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.
Step-by-step explanation:
We are given that one wants to estimate the mean PSLT for the population of all families in New York City with gross incomes in the range $35.000 to $40.000.
If sigma equals 2.0, we have to find that how many families should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5.
Here, we will use the concept of Margin of error as the statement "true mean PSLT within 0.5" represents the margin of error we want.
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<u>SO, Margin of error formula is given by;</u>
Margin of error =
where,
= significance level = 10%
= standard deviation = 2.0
n = number of families
Now, in the z table the critical value of x at 5% (
) level of significance is 1.645.
SO, Margin of error =
0.5 =

n =
= 43.3 ≈ 43
Therefore, number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.
<span>No sé la forma correcta de hacerlo, pero encontrar conjuntos de dos números que pueden igualar 12, luego encontrar cuál de los encaja en la segunda ecuación correctamente.</span>