First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at
, the equation will contain a
term.
If we start with
we have a parabola, concave down, with vertex at
and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be ![(4, 7)](https://tex.z-dn.net/?f=%20%284%2C%207%29%20)
We have
![y = -(x-4)+7](https://tex.z-dn.net/?f=%20y%20%3D%20-%28x-4%29%2B7%20)
Now we only have to fix the fact that this parabola doesn't land at
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
![y = a(x-4)^2+7](https://tex.z-dn.net/?f=%20y%20%3D%20a%28x-4%29%5E2%2B7%20)
such that:
Plugging these values gets us
![0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}](https://tex.z-dn.net/?f=%200%20%3D%20a%288-4%29%5E2%2B7%20%5Ciff%2016a%2B7%3D0%20%5Ciff%20a%20%3D%20-%5Cdfrac%7B7%7D%7B16%7D)
As you can see in the attached figure, the parabola we get satisfies all the requests.
Answer:
A. divide both sides by 3
Step-by-step explanation:
3p < 14
We want to isolate p, so we divide both sides by 3
3p/3 < 14/3
p <14/3
Answer:
For the first one it is D.
Step-by-step explanation:
I added 84.6 and 30.4 which gives me 115. I then added 66 to get 181, triangles angles only add up to 180 degrees, therefore they are not similar.
You could buy the Magnet and the Postcard and get 19 cents!
Answer:
px-qx
Step-by-step explanation: