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3 years ago

What is the solution to the system of equations?

Mathematics

1 answer:

Natalka [10]3 years ago

5 0

Answer:

x = 1 y = 3 z = 1

Step-by-step explanation:

(1) x - 3y - z = -9 (2) -2x + y + 2z = 3 (3) 2x + y + 3z = 8

2x(1) 2x - 6y - 2z = -18 (2) -2x + y + 2z = 3

- 5y = -15 2y + 5z = 11

y = 3 2(3) + 5z = 11

6 + 5z = 11

5z = 5

z = 1

x - 3(3) - 1 = -9

x - 9 - 1 = -9

x - 10 = -9

x = 1

Note: If you write your equations across your paper, then the work can just flow down the paper. It makes it so much easier to show the work you have done. OK?

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Use the distributive property to write equivalent expressions. Someone please help, ty!

earnstyle [38]

Answer:

For the question below, you will need to find the GCF of 45 and 60. In this instance it is 5, so it will be outside the box. The GCF answers will be inside the parenthesis, which is 7 and 12.

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Hope this helped.

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3 years ago

Select the correct answer

Kaylis [27]

Answer:

B. 1.-1,-2

Step-by-step explanation:

$g(x) = x ^{3} + 2 {x}^{2} - x - 2$

Substitute g(x)=0

$0 = {x}^{3} + 2 {x}^{2} - x - 2$

Move the expression to the left

$0 - {x}^{3} - 2 {x}^{2} + x + 2 = 0$

Factor out -x^2 from the expression

$- {x}^{2} \times (x + 2) + x + 2 = 0$

Factor out (x+2) from the expression

$(x + 2) \times ({x}^{2} + 1) = 0$

When the product of the factor equals 0, at least one factor is 0

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$- {x}^{2}+ 1 > = 0$

Solve for x

$x = - 2 \\ x = - 1\\ x = 1$

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3 years ago

What is the probability of tossing a coin three times and getting tails each time?

telo118 [61]

Answer:

1/8

Step-by-step explanation:

This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.

The probability of flipping tails is 1/2. We need three of these.

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3 years ago

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3 years ago

What is your sister’s total cost under each of the two plans?2. Suppose your sister doubles her monthly usage to 3,500 minutes a

chubhunter [2.5K]

Answer:

(1) The total cost under Plan A is $92 and the total cost under Plan B is $515.

(2) The total cost under Plan A is $92 and the total cost under Plan B is $1,030.

Step-by-step explanation:

The question is incomplete, so the complete question is below:

$A\ cell \ phone \ company\ offers\ two \ different \ plans.$

$Plan\ A\ costs\ \$92\ per\ month\ for\ unlimited\ talk\ and\ text.\ Plan\ B\ costs \ $0.20\ per\ minute\ plus\ \$0.10\ per\ text\ message\ sent.$ $You\ need \ to\ purchase \ a \ plan \ for\ your \ 14-year-old \ sister$ $.Your\ sister\ currently \ uses\ 1,750 \ minutes\ and \ sends\ 1,650 \ texts\ each \ month.$ $(1) What\ is\ your \ sister's\ total\ cost\ under \ each\ of\ the\ two\ plans?$

$(2) Suppose\ your\ sister\ doubles\ her\ monthly\ usage \ to\ 3,500\ minutes \ and\ sends\ 3,300 \ texts.$ $What \ is \ your \ sister's \ total \ cost \ under \ each \ of \ the \ two \ plans?$

Now, to find (1) total cost for each of the two plans. (2) Total cost under each of the two plans, if sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.

As, the Plan A is for unlimited talk and text

Cost of the Plan A = $92.

Now, to find the cost under Plan B:

According to question:

Rate of call per minute is $0.20 and per text is $0.10.

Calls she uses currently is 1,750 minutes and text 1,650.

So, to get the cost of Plan B:

$0.20\times 1750+0.10\times 1650$