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navik [9.2K]
4 years ago
14

The temperature in a room is 56°C. What would the velocity of a sound wave be at this temperature?

Physics
2 answers:
pantera1 [17]4 years ago
8 0

Answer:

C

Explanation:

The units of velocity are m/s, not Hz.  Make sure you wrote it correctly.

The speed of sound in air at sea level is approximately:

v ≈ 331.4 + 0.6 T

where v is velocity in m/s and T is the temperature in Celsius.

At 56°C:

v ≈ 331.4 + 0.6 (56)

v ≈ 365 m/s

The closest is C.

nikdorinn [45]4 years ago
6 0

Answer: The CORRECT answer is C. 364.6 Hz

Explanation: I took the test and I got it RIGHT!

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A 2.5kg object oscillates at the end of a vertically hanging light spring once every 0.65s .
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Explanation:

By the general expresion for this problem, we have:

y(t) = A*cos(w*t+∅)

since: w = 2π/T = 2π/0,65  

For the initial conditions:

y(0) = (0.17cm)*cos(w*0+∅) = + 0.17 m ---> cos(∅) = 1 ---> ∅ = 0°

Then:

A) y(t) = (0.17 m)*cos((2π/0,65)*t)

<u>B part</u>

This means, find the first solution for:

y(t) = (0.17 m)*cos((2π/0,65)*t) = 0 > (equilibrium position)

then: cos((2π/0,65)*t) = 0 ---> (2π/0,65)*t = π/2 ---> t = 0.1625 sec

<u>C part</u>

By definition: (Velocity) v = dy/dt

Then, deriving: v = dy/dt = - (0.17 m)*(2π/0,65)*sin((2π/0,65)*t)

The maximum velocity ocurrs when sin((2π/0,65)*t)  = ±1, then (in absolute value): Vmax = 1,64 m/s

<u>D part</u>

By definition: (Aceleration) A = dv/dt

Then, deriving: v = dv/dt = - (0.17 m)*(2π/0,65)²*cos((2π/0,65)*t)

The maximum aceleration ocurrs when cos((2π/0,65)*t)  = ±1, then (in absolute value): Amax = 15,88 m/s²

<u>E part</u>

<em>For the acceleration</em>, ocurres by all the solution when:

cos((2π/0,65)*t)  = cos(phase) = ±1, this means: phase = {π, 2π, 3π, ...}, all π multiples.

Then, for the position:

<em>y(t) = (0.17 m)*±1= {+0.17 m ; -0.17 m}</em>

<em>For the velocity</em>, ocurres by all the solution when:

sin((2π/0,65)*t)  = sin(phase) = ±1, this means: phase = {π/2, π, 3π/2, ...}, all π/2 multiples.

Then, for the position:

<em>y(t) = (0.17 m)*cos(phase)= 0</em>

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Answer:

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We see that we have a positive acceleration and that is what we are going to use in the parabolic motion equations

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