We are given the molecular mass of tetraoxosulphate(VI) acid as 98 g/mol. The molecular formula of this is H₂SO₄ which is also known as sulfuric aid. The vapour density of a substance is the density of a vapour in relation to hydrogen gas. Therefore, it the mass of a volume of gas, divided by the mass of the same volume of hydrogen gas. We can use the following formula:
vapour density = molar mass of gas/ molar mass of H₂
vapour density = 98 g/mol H₂SO₄ / 2 g/mol H₂
vapour density = 49
The vapour density of tetraoxosulphate(IV) acid is found to be 49. It should also be noted that the vapour density is a unitless quantity.
Answer:
150g
Explanation:
Assuming they are ideal gases at the same temperature and pressure, equal moles of gasses have equal volume. IN this case, if we have 10g of hydrogen gas, that is 5 moles of H2 gas. That means 5 moles og NO2 will occupy the same volume which is 5*(14.0 + 16.0*2) = 230 g
Answer:
1.196 M NaOH
Explanation:
Molarity = moles/Volume (L)
moles NaOH = mass NaOH/MM NaOH = 12/40.01 = 0.299 moles NaOH
Volume solution = 250 mL = 0.250L
M = 0.299/0.250=1.196 M NaOH
Ammonium hydroxide is basic
Reaction:
FeCl3(aq) + 3AgNO3(aq) → Fe(NO3)3(aq) + 3AgCl(s)
Net ionic:
Ag + (aq) + Cl − (aq) → AgCl(s)
Explanation:
The evidence that a double replacement reaction has happened is the formation of a solid, liquid or gas from aqueous solutions. I’m this case case silver chloride is a precipitate.