Question

When shooting two consecutive free throws

Answer 1

Answer:

89.44%.

Step-by-step explanation:

Let's work out the probability he misses both throws:

Prob( he misses both throws) =  (1-0.78) * ( 1 - 0.52)

= 0.22*0.48

= 0.1056.

So the probability he makes at least one free throw = 1 - 0.1056

= 0.8944.

(It is 1 - 0.1056 because the default of missing  both throws is either  making one throw  on first or second attempt, or making both throws).